# What are the roots of f(x) = x^{2} - 48?

**Solution:**

Given, f(x) = x^{2} - 48

We have to find the roots of the function.

To find the roots equate the function to zero.

x^{2} - 48 = 0

x^{2} = 48

Now taking square root,

x = √48

x = √16×3

So we get

x = ±4√3

x = +4√3 and -4√3

Therefore, the roots of the function are x = +4√3 and -4√3.

## What are the roots of f(x) = x^{2} - 48?

**Summary:**

The roots of f(x) = x^{2} - 48 are x = +4√3 and -4√3. To find the roots equate the function to zero.

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